Low 1 c question

[Rolgoat]

Are parallel space-time continuums scaled as low 1 c because they do not intersect on any axis?

 

[Georredannea15]

Well, depends on whether you can use the universes as measuring sticks for distances in the depiction or not.
Usually, you can not, because they are depicted as floating bubbles or lines or whatever which don't really depict proper size, and in that case I would say no to all of them. If you can use them in a way to measure the size of the 5D space to prove it's significantly large, then you could get somewhere. But... yeah, depicting 5D space in a way that conserves size is just pretty hard.

Space being infinite in itself doesn't matter, as space at that level is infinite in some sense anyway. You would need to be told that either specifically its 5 dimensional volume is infinite or that specifically the 5th dimensional axis (the one you add to the standard timelines) is infinite (or very large) for that to work. But I figure if you have information that specific then you wouldn't need this thread. In general, infinite could mean infinite by 3D or 4D standards, or in the sense of countably infinite times larger than a spacetime continuum, so that is just not enough.

In short, no, the 4th dimensional volume has 0 volume in the 5th dimensional volume (i.e. the extending vertical axis), so they never intersect on this vertical axis. But this is not Low 1-C because the 5th dimensional axis, i.e. the perpendicular axis, would have to extend infinitely or significantly. Otherwise it would be a curved axis and not Low 1-C.