Voltage with Fusion Power

[CNBA3]

With the previous thread, I decided to start fresh with a new one with more cohesive structure based on Fusors using electrical fields for nuclear fusion.



For why KeV is converted into Voltage is to apply Ohm's Law later on as some of the links from the previous thread that 30 KeV would be efficient for the practice. with conversion using the Coulombs (1.60217663e-19), you get around 30000 volts.


For the material I will be using Tungsten ( Ohm/m)


Ohm's would apply here since voltage is a force that carries the charged particles through a conductor as Fusors have Electrodes which are conductors that allows for electricity to move in and out of the object/substance/region.


To find Ohms you would multiply the Ohms/meter with the distance in meters, I will be using the electrodes inside the container instead of the whole thing which is (4.9e-8 * .07) = 3.43e-9 Ohms.


Then we find the Amps which is 30000 volts / 3.43e-9 Ohms = 8.7463557e+12 amps


Then we find the watts which is multiplying volts by amperes = 2.6239067055394E+17 watts = 2.6239067055394E+17 joules/seconds


As for the energy requirement issues, the verse in question transcends conventional science and they have unlimited resources.

@Damage3245 @AbaddonTheDisappointment @KLOL506 @CloverDragon03

 

[CNBA3]

bump

 

[CNBA3]

Bump

 

[CNBA3]

Bump

 

[MusicRelaxing]

Bump

Would this work with normal lightning?

 

[MusicRelaxing]

Wait. Nope. Nevermind;mb.

 

[CNBA3]

Would this work with normal lightning?

Technically yes but you would have to use the Ohms for that of air which it travels through.

 

[MusicRelaxing]

Technically yes but you would have to use the Ohms for that of air which it travels through.

Can you provide it for me?

 

[CNBA3]

Can you provide it for me?

Misakas Lightning energy calculation

vsbattles.fandom.com

I am not sure if you should use 1015 Ohms/meters for the one above

or this one here below

1e+15 - 1e+13 Ohms/meters

https://agupubs.onlinelibrary.wiley.com/doi/full/10.1002/jgra.50478#:~:text=The%20electric%20resistivity%20of%20air%20is%20found%20to%20vary%20between,with%20changes%20in%20electric%20field.

 

[MusicRelaxing]

Misakas Lightning energy calculation

vsbattles.fandom.com

I am not sure if you should use 1015 Ohms/meters for the one above

or this one here below

1e+15 - 1e+13 Ohms/meters

https://agupubs.onlinelibrary.wiley.com/doi/full/10.1002/jgra.50478#:~:text=The%20electric%20resistivity%20of%20air%20is%20found%20to%20vary%20between,with%20changes%20in%20electric%20field.

Hmm. Aight. I wonder how this would conflict with pixel scaling and stuff? How it would change it and stuff.

 

[CNBA3]

Hmm. Aight. I wonder how this would conflict with pixel scaling and stuff? How it would change it and stuff.

What matters really is when you got to find Ohms, is to find the Ohms/meter by what material the voltage is channeled through, and then multiply by the length in meters which is the pixeled stuff which the voltage is channeled through to get the Ohms or resistance.

 

[MusicRelaxing]

What matters really is when you got to find Ohms, is to find the Ohms/meter by what material the voltage is channeled through, and then multiply by the length in meters which is the pixeled stuff which the voltage is channeled through to get the Ohms or resistance.

Alright... doing some experimentation with it. What would the voltage even be? By what the material is channelled through? If so, what about for lightning calcs? Do you just use the volts for lightning? How do you even find the volts anyways?

 

[Greatsage13th]

Following

 

[CNBA3]

Alright... doing some experimentation with it. What would the voltage even be? By what the material is channelled through? If so, what about for lightning calcs? Do you just use the volts for lightning? How do you even find the volts anyways?

if it is natural lightning or anything that supports it being close to real lightning, I would say use the voltage for that is 300 million.

 

[MusicRelaxing]

if it is natural lightning or anything that supports it being close to real lightning, I would say use the voltage for that is 300 million.

I was doing the formula, and uh... the results hit Large Planet. Can you do an example using the averages of lightning? I'm P curious about it.

 

[CNBA3]

I was doing the formula, and uh... the results hit Large Planet. Can you do an example using the averages of lightning? I'm P curious about it.

I am not sure about the example, remember, I am not sure which of the air ohms/meters values to use. try using 30000 amps too.

 

[MusicRelaxing]

I am not sure about the example, remember, I am not sure which of the air ohms/meters values to use. try using 30000 amps too.

I used the one you provided, the one in the positives resulted in a weirdly high number. Could you find a source of it actually being 1015 ohms/meter? Cause the site DT's calc links to is long gone.

 

[MusicRelaxing]

"Luftionen sind Moleküle, die ein Elektron verloren oder hinzugewonnen haben. Solche Ionen sind bereits in der „natürlichen“ Luft vorhanden, werden aber bei Filterung und technischer Aufbereitung entfernt. In natürlicher Umgebung entstehen Luftionen vorwiegend durch ionisierende Strahlung. Trotzdem ist Raumluft normalerweise ein recht guter Isolator mit einem spezifischen Widerstand von über 1015 Ohm/Meter. Durch Steigerung der Ionenzahl kann der spezifische Widerstand der Luft auf 1011 Ohm/Meter gesenkt werden – Resultat ist eine verbesserte elektrische Leitfähigkeit."
Putting it into DEEPL, which means...
"Air ions are molecules that have lost or gained an electron. Such ions are already present in "natural" air, but are removed during filtering and technical treatment. In natural environments, air ions are created primarily by ionizing radiation. Nevertheless, room air is normally a fairly good insulator with a resistivity above 1015 ohms/meter. By increasing the number of ions, the resistivity of air can be lowered to 1011 ohms/meter - resulting in improved electrical conductivity."

 

[CNBA3]

I used the one you provided, the one in the positives resulted in a weirdly high number. Could you find a source of it actually being 1015 ohms/meter? Cause the site DT's calc links to is long gone.

I couldn’t either

 

[MusicRelaxing]

I couldn’t either

I found it above and tried; 4000 meters even though wiki standard is 2000.

1015 Ω * m/4000 meters = 0.25 ohms
300,000,000 Volts/0.25 ohms = 1200000000 amperes x 300,000,000 Volts = 3.6 × 10^17 watts. Thats MASSIVELY over the normal lightning, is there anything to avoid wanked results?

 

[CNBA3]

I found it above and tried; 4000 meters even though wiki standard is 2000.

1015 Ω * m/4000 meters = 0.25 ohms
300,000,000 Volts/0.25 ohms = 1200000000 amperes x 300,000,000 Volts = 3.6 × 10^17 watts. Thats MASSIVELY over the normal lightning, is there anything to avoid wanked results?

use 30000 amperes as that is for lightning

 

[MusicRelaxing]

use 30000 amperes as that is for lightning

So... I'm supposed to find volts through that? or?

 

[CNBA3]

So... I'm supposed to find volts through that? or?

You can find watts through that with multiplying volts with amps which is around 9e+12 watts

 

[MusicRelaxing]

You can find watts through that with multiplying volts with amps which is around 9e+12 watts

I found it above and tried; 4000 meters even though wiki standard is 2000.

1015 Ω * m/4000 meters = 0.25 ohms
300,000,000 Volts/0.25 ohms = 1200000000 amperes x 300,000,000 Volts = 3.6 × 10^17 watts. Thats MASSIVELY over the normal lightning, is there anything to avoid wanked results?

Yea. I did, I'm asking what process do you have to do to find amperers that is that small? Cause the way I did it had it be wayyy bigger.

 

[CNBA3]

Yea. I did, I'm asking what process do you have to do to find amperers that is that small? Cause the way I did it had it be wayyy bigger.

I just did a search on Google to find the results of the amperes

 

[CNBA3]

Following

thanks

So I found out on the matter how Plasma devices like Fusors can't really get good results with Voltage since it's resistance fluctuates.

 

[CNBA3]

Following

thanks

So I found that for Plasma devices like Fusors can't really use equations like Ohm's law because they fluctuate, and the minimal you can use for such processes is 10mA at 30kV.

https://experiment.com/projects/bac... needs at least,the high voltage feed through.