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So, is the idea that the Lorentz-transformation does a 1/γ(r) for the length contraction since mass is divided by volume that gets inverted into an added γ(r)? Or what are your steps?Bump
Edit: on a second thought, I'm not sure if that'll work since I have no idea how to adjust t to that. So I'll go with density increasing which will add extra γ(r). For example case 1 will look like that:
2πϱHc² ∫₀ᴿ (γ(r) - 1) γ(r) r dr =
2πϱHc² ∫₀ᴿ (1/(1 - V²r²/(R²c²)) - 1/√(1 - V²r²/(R²c²))) r dr
It's just either replacing dr by γ(r) * dr or rho by γ(r) * rho, you can think either way.So, is the idea that the Lorentz-transformation does a 1/γ(r) for the length contraction since mass is divided by volume that gets inverted into an added γ(r)? Or what are your steps?
Sure, but why are you making these replacements?It's just either replacing dr by γ(r) * dr or rho by γ(r) * rho, you can think either way.
Because differential thickness we measure dr is Lorentz-contracted compared to proper thickness (say dr0) and relation would be dr = dr0/γ(r). For proper mass, we should use proper values.Sure, but why are you making these replacements?
So, is the idea that the Lorentz-transformation does a 1/γ(r) for the length contraction since mass is divided by volume that gets inverted into an added γ(r)? Or what are your steps?
Bump.Because differential thickness we measure dr is Lorentz-contracted compared to proper thickness (say dr0) and relation would be dr = dr0/γ(r). For proper mass, we should use proper values.
Alternatively if we go with density, you'd multiply it by γ(r) if object as a whole was moving at same speed right? I'm doing same thing, just locally.
Edit: reread your last post and yeah that's the idea.
Thanks! I'll edit the OP according to that a little later and call some CGMs. Putting you as agree then.A thoroughly written proof would be ideal, but this is probably fine like that. We gotta need a second proper evaluation, though.
Thanks for evaluation.The revised method should be fine
I believe spherical case is uncommon for cloud feats.unless the KE feats page gets modified to include omnidirectional feats, I would assume this would go on the cloud calculations page since that's where the regular omnidirectional ke formulas are at
I can already think of one example via luffy dispersing's enel raigoI believe spherical case is uncommon for cloud feats.
Formulas are already accepted. I also made a calculator and now we need to decide how to implement them (for example adding to KE feats page, creating its own page, adding to clouds calcs page, etc.).Could've sworn I already posted in here
What's left to do here?
BumpFormulas are already accepted. I also made a calculator and now we need to decide how to implement them (for example adding to KE feats page, creating its own page, adding to clouds calcs page, etc.).
This would work best imo(for example adding to KE feats page