The force of punching the Chicxulub meteor to oblivion?

[DeathstroketheHedgehog]

I was comparing two ocs that were not mine for a battle debate in another wiki. One of said ocs traveled just to the stratosphere to punch and obliterate a meteor that was similar in size to the Chicxulub meteor. Of course, since the meteor was only a couple of miles wide, I don't expect it to be at 6-B by its impact force, but then again, I don't know how to calculate any of the other factors, such as the speed of the meteor, the out of kinetic energy released upon obliteration, air resistance, etc.

So how strong would one have to be to perform this feat? P.S., it would be helpful if I see the formula myself to use for later purposes.

 

[TheJ-ManRequiem]

Meteor density of 5 grams per square centimeter, meteor velocity is 11km/s to 72km/s. Make of that what you will.

 

[TheJ-ManRequiem]

Did a rough calc assuming it was 2 square miles and was 11km/s itd be 3 megatons of kinetic energy, OC dude would need to be at least > that. Probably far higher.

 

[DeathstroketheHedgehog]

Do you have the formula of the calc that you used?

 

[DeathstroketheHedgehog]

Does anyone else have a formula template(?) I can use for later on?

 

[TheJ-ManRequiem]

I just used 5 grams per square centimeter to get a mass for it (assuming it was 2 square miles) and used 11km/s for its speed to get a kinetic energy, of course it was a rough calc, I didn't account for stuff like drag and reentry, etc but it'd be in the same ballpark.

 

[DeathstroketheHedgehog]

Okay then... I think I could work with that.

 

[TheJ-ManRequiem]

http://www.csgnetwork.com/kineticenergycalc.html Kinetic energy calculator http://www.calculator.net/volume-calculator.html Volume calculator. If ya had a pic of the meteor and at least one of its dimensions i could go even further in accuracy. But for your future yse these are decent.

 

[DeathstroketheHedgehog]

Thanks

 

[TheJ-ManRequiem]

I messed up, I think I got square centimeter/miles mixed up with cubic centimeter and miles so I redid it but using cubic stuff, 602.6 gigatons. If im wrong ignore it and use the previous one.

 

[DeathstroketheHedgehog]

Ill check on it now, but thanks for letting me know.

 

[TheJ-ManRequiem]

The latter looks more correct to me.

 

[DeathstroketheHedgehog]

I went by your formula and got a different answer, but it is still right in the same ballpark, thanks.

 

[TheJ-ManRequiem]

Eh, mine was really rough so it was a given.

 

[Chu_Minh_Duy]

Saitama would do that with ease