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As it currently stands, Large Size Type 4 is written as follows:
"Characters so huge that it would be easily viewable from the surface of the planet when viewed from space. These characters are usually able to generate global catastrophes and high-end natural disasters. Characters here have a size that is millions of km²."
This doesn't line up with the idea that size is seen as 3D under current standards outside our current ideals for Type 9 Small Size (although Ogurtsow's proposals sound much better as they account for the fact that we can very easily see 11-A characters on TV sets: https://vsbattles.com/threads/small-size-revision.149018/post-5612925 ) and our current ideals for Type 9 Large Size and higher. There are plenty of reasons as to why this doesn't work.
First, there's the space definition. Space is defined quite arbitrarily. The current definition for space is anything above the Karman Line, which is 100 kilometers above Earth's surface. At that height, you can see the Palm Jumeirah and all its fronds:
The Palm Jumeirah isn't all that big; according to a travel site, the Palm Jumeirah is nowhere near millions of square kilometers; in fact it's only 560 hectares: https://www.bayut.com/area-guides/palm-jumeirah/
Near where the ISS would be (254 miles, or 408.8 km), you can make out the structure of the Faroe Islands:
You can make out the distinguishable shape of each island, including Sandoy, which has an area of 125 km²: https://en.wikipedia.org/wiki/Sandoy
Bear in mind, unlike GPS satellites, the ISS is inhabitable. Speaking of, at around 20200 km (the altitude of GPS satellites), you can see islands like Newfoundland, Iceland, Cuba and Hispaniola (the latter two pictured because Google Earth likes to throw clouds on the model):
Even Florida is visible and its area is 65,758 km²: https://en.wikipedia.org/wiki/Florida
If circles were made for each entity, this is the diameter each circle needs to be to match the size of the entities pictured.:
Palm Jumeirah-sized circle (visible from Karman Line): 2.670232471 km
Sandoy-sized circle (visible from ISS): 12.61566261 km
Florida-sized circle (visible from a GPS satellite): 289.3539113 km
And if that isn't enough, you can faintly see CYPRUS from a GPS satellite: https://prnt.sc/jugRmFherIk2
Granted you couldn't make out its horseshoe crab shape (unlike with Florida where you can see that it's a penis), but you can certainly see Cyprus. It's area is 9251 km² (equivalent to a circle with a diameter of 108.5298992 km): https://en.wikipedia.org/wiki/Cyprus
Then there's the area thing. Millions of square kilometers? Let's see... Type 2 and Type 3 Large Size defines sizes with representable figures. For Type 2, it's skyscrapers, which are defined at 100 meters tall, and for Type 3, it's mountains, although Type 3 is a bit bigger than current definitions of mountains, which range from 1000 to 2000 feet depending on where you get 'em from. You would need to pull the entirety of Scandanavia off of Europe if you want a representative figure for Large Size Type 4. Now, we usually use living entities like humans, mammals, fish, and the like for size measurements. Let's use a Great Barracuda for this exercise, as it's one of the most streamlined fish out there.:
These guys can go for 60 to 100 centimeters in length. We'll use the latter figure as that corresponds to exactly 1 meter.
Looking at the barracuda lengthwise, a barracuda-sized block would have an area of 0.1465053763 m² and a volume of 0.01592838399 m³. The total area of Scandanavia; which consists of Finland, Sweden, Norway, and Denmark, is 1213720 km². That's 8.284474128*10^12 times the area of a barracuda-sized block, with each dimension being 2878276.243 times the size of the barracuda. As such, a Scandanavia-sized barracuda should have a width of 312932.44996709 meters (312.93 km). For comparison, the highest point in Scandanavia is a mountain 2469 meters tall: https://en.wikipedia.org/wiki/Galdhøpiggen
That's 126.7 times smaller than the width of the Scandanavia-sized barracuda. This means that a barracuda-sized block with Scadanavia thickness would proportionally only be 857.8050861 micrometers: only 8 times as thick as a sheet of paper. And yet, that's thinner than a flatworm, which is 1 mm thick and 8-10 cm long according to a Singapore wildlife fact sheet (http://www.wildsingapore.com/wildfacts/worm/polycladida/polycladida.htm ).
Let's also use the Amazon Rainforest: https://en.wikipedia.org/wiki/Amazon_rainforest
The forest itself is 5500000 km² in area, yet it's highest point is only 2995.3 meters high: https://en.wikipedia.org/wiki/Pico_da_Neblina
That's 3.75412844*10^13 times the area of the barracuda-sized block, with each dimension being 6127094.287 times the size of the barracuda. A barracuda with the same area as the Amazon Rainforest would need to be 666151.0101 meters (666.15 km) wide, and yet... The highest point in the Amazon would make the block proportionally THINNER. If the Amazon-sized Barracuda Block is the size of a barracuda, it would be 222.4x thinner, which equates to 488.86 micrometers thick.
Barracudas should never be sub-millimeters in width; you should know that, wiki!
That being said, a Scadanavia-sized barracuda would have 2.384500507*10^19 times the mass of a normal barracuda (9 kg for a 1-meter-long barracuda), or 2.146050456*10^20 kg. Assuming the exact same locomotion as a normal barracuda (including its swiftness), it would be going 45034661.4 m/s (based on the barracuda's top speed of 35 miles an hour, or 15.6464 m/s). This equates to 221376260454323239670809157763912804 joules from the relativistic KE calc: https://prnt.sc/XkrlK_gf23d5
That's 221376.2605 quettajoules or 52.91 yottatons of TNT. The Scadanavia-sized barracuda is more than enough to destroy Earth just by ramming into it, never mind cause high-end natural disasters. For reference, the largest recorded earthquake has a magnitude of 9.5 and let out an energy of 2.68 gigatons of TNT. Hurricanes cause wider-scale destruction than earthquakes and they let out 130 petajoules (31.07 megatons of TNT) per day.
A barracuda only needs to be 1600 meters (1.6 kilometers) long just for its proportional KE to match a Magnitude 9.5 earthquake: https://prnt.sc/DF4ldbTm3RMS
Under our current earthquake calc formulae, assuming a Richter magnitude of 5 and a distance of 20037.5 km (half the circumference) is enough to be considered a global earthquake, the earthquake would be sitting at a magnitude of 12.23: https://prnt.sc/KXQI66Y74G51
That's equal to 33.7 teratons of TNT: https://prnt.sc/hS4yfplOgSTl
Let's use this formula for large size KE: (x³m)(x*v)²/2; x is how many times larger than normal a creature is, m is the mass, and v is the velocity.
Basing things off this, you'd need a barracuda that's 10505.96721 meters. That itself would make the barracuda visible from the ISS.
If it were a human, it'd be more like this:
Multiply that by the average height of 5'9" (1.7526 meters) and you get the height requirement of 18946.87503 meters for a human's KE to cause a global earthquake.
As such, ideally, we should better define or break up Type 4 Large Size. The minimum requirements for visibility from space (assuming 1 arcminute as the smallest visible angle) is as such (figures done when angle is set to "Minutes" and 8 sig figs are set): https://www.1728.org/angsize.htm
Karman Line (100 km; current definition of space): 29.088821 meters
ISS (408.773376 km): 118.90736 meters
GPS Satellite (20200 km): 5875.9419 meters
As for the figures required to cause a global earthquake (Magnitude 5 at the furthest point touchable on Earth), here's what I got.:
Great Barracuda (thin organism): 10505.96721 meters (block area of 16.171 km²)
Human (often used as a base for VBW): 18946.87503 meters (cross-sectional area of 244.11 km² based on human cross-sectional area of 0.68 m²)
As for the area nonsense... Yeah, get rid of it. If you can see and make out Florida's shape from a GPS satellite, then maybe the millions of square kilometers thing should be considered a stupid idea.
By the way, I was able to distinguish 1-millimeter-tall letters on a small ruler from half a meter, which is 6.87 arcminutes. Using that figure means I can distinguish the shape of something that's 40.4 km in size if I'm on a GPS satellite.
If a new size tier is required after the Type 4 Large Size fix, I considered something like this:
"Type 5 (Lunar): At this size, the character would be large enough to be visible if he or she were as far from us as the moon is. Characters starting at X km fit this memo"
This would be as such:
Minimum Visible (1 arcminute): 111.8 km
Minimum Distinguishable (based on my ruler eyeballing): 768.8 km
So yeah, there you have it.
"Characters so huge that it would be easily viewable from the surface of the planet when viewed from space. These characters are usually able to generate global catastrophes and high-end natural disasters. Characters here have a size that is millions of km²."
This doesn't line up with the idea that size is seen as 3D under current standards outside our current ideals for Type 9 Small Size (although Ogurtsow's proposals sound much better as they account for the fact that we can very easily see 11-A characters on TV sets: https://vsbattles.com/threads/small-size-revision.149018/post-5612925 ) and our current ideals for Type 9 Large Size and higher. There are plenty of reasons as to why this doesn't work.
First, there's the space definition. Space is defined quite arbitrarily. The current definition for space is anything above the Karman Line, which is 100 kilometers above Earth's surface. At that height, you can see the Palm Jumeirah and all its fronds:
The Palm Jumeirah isn't all that big; according to a travel site, the Palm Jumeirah is nowhere near millions of square kilometers; in fact it's only 560 hectares: https://www.bayut.com/area-guides/palm-jumeirah/
Near where the ISS would be (254 miles, or 408.8 km), you can make out the structure of the Faroe Islands:
You can make out the distinguishable shape of each island, including Sandoy, which has an area of 125 km²: https://en.wikipedia.org/wiki/Sandoy
Bear in mind, unlike GPS satellites, the ISS is inhabitable. Speaking of, at around 20200 km (the altitude of GPS satellites), you can see islands like Newfoundland, Iceland, Cuba and Hispaniola (the latter two pictured because Google Earth likes to throw clouds on the model):
Even Florida is visible and its area is 65,758 km²: https://en.wikipedia.org/wiki/Florida
If circles were made for each entity, this is the diameter each circle needs to be to match the size of the entities pictured.:
Palm Jumeirah-sized circle (visible from Karman Line): 2.670232471 km
Sandoy-sized circle (visible from ISS): 12.61566261 km
Florida-sized circle (visible from a GPS satellite): 289.3539113 km
And if that isn't enough, you can faintly see CYPRUS from a GPS satellite: https://prnt.sc/jugRmFherIk2
Granted you couldn't make out its horseshoe crab shape (unlike with Florida where you can see that it's a penis), but you can certainly see Cyprus. It's area is 9251 km² (equivalent to a circle with a diameter of 108.5298992 km): https://en.wikipedia.org/wiki/Cyprus
Then there's the area thing. Millions of square kilometers? Let's see... Type 2 and Type 3 Large Size defines sizes with representable figures. For Type 2, it's skyscrapers, which are defined at 100 meters tall, and for Type 3, it's mountains, although Type 3 is a bit bigger than current definitions of mountains, which range from 1000 to 2000 feet depending on where you get 'em from. You would need to pull the entirety of Scandanavia off of Europe if you want a representative figure for Large Size Type 4. Now, we usually use living entities like humans, mammals, fish, and the like for size measurements. Let's use a Great Barracuda for this exercise, as it's one of the most streamlined fish out there.:
These guys can go for 60 to 100 centimeters in length. We'll use the latter figure as that corresponds to exactly 1 meter.
A barracuda is 744 px long and 109 px tall in the first picture. The barracuda's head is 90 px tall. In the second picture, the barracuda's head is 1414.6 px tall, and the barracuda is 1271.4 px wide. Let's see the proportions:
Length: 1 meter
Height: 109/744=0.1465053763 meters
Head Height: 90/744=0.1209677419 meters
Width: (1271.4/1414.6)*(90/744)=0.1087221738 meters
Length: 1 meter
Height: 109/744=0.1465053763 meters
Head Height: 90/744=0.1209677419 meters
Width: (1271.4/1414.6)*(90/744)=0.1087221738 meters
Looking at the barracuda lengthwise, a barracuda-sized block would have an area of 0.1465053763 m² and a volume of 0.01592838399 m³. The total area of Scandanavia; which consists of Finland, Sweden, Norway, and Denmark, is 1213720 km². That's 8.284474128*10^12 times the area of a barracuda-sized block, with each dimension being 2878276.243 times the size of the barracuda. As such, a Scandanavia-sized barracuda should have a width of 312932.44996709 meters (312.93 km). For comparison, the highest point in Scandanavia is a mountain 2469 meters tall: https://en.wikipedia.org/wiki/Galdhøpiggen
That's 126.7 times smaller than the width of the Scandanavia-sized barracuda. This means that a barracuda-sized block with Scadanavia thickness would proportionally only be 857.8050861 micrometers: only 8 times as thick as a sheet of paper. And yet, that's thinner than a flatworm, which is 1 mm thick and 8-10 cm long according to a Singapore wildlife fact sheet (http://www.wildsingapore.com/wildfacts/worm/polycladida/polycladida.htm ).
Let's also use the Amazon Rainforest: https://en.wikipedia.org/wiki/Amazon_rainforest
The forest itself is 5500000 km² in area, yet it's highest point is only 2995.3 meters high: https://en.wikipedia.org/wiki/Pico_da_Neblina
That's 3.75412844*10^13 times the area of the barracuda-sized block, with each dimension being 6127094.287 times the size of the barracuda. A barracuda with the same area as the Amazon Rainforest would need to be 666151.0101 meters (666.15 km) wide, and yet... The highest point in the Amazon would make the block proportionally THINNER. If the Amazon-sized Barracuda Block is the size of a barracuda, it would be 222.4x thinner, which equates to 488.86 micrometers thick.
Barracudas should never be sub-millimeters in width; you should know that, wiki!
That being said, a Scadanavia-sized barracuda would have 2.384500507*10^19 times the mass of a normal barracuda (9 kg for a 1-meter-long barracuda), or 2.146050456*10^20 kg. Assuming the exact same locomotion as a normal barracuda (including its swiftness), it would be going 45034661.4 m/s (based on the barracuda's top speed of 35 miles an hour, or 15.6464 m/s). This equates to 221376260454323239670809157763912804 joules from the relativistic KE calc: https://prnt.sc/XkrlK_gf23d5
That's 221376.2605 quettajoules or 52.91 yottatons of TNT. The Scadanavia-sized barracuda is more than enough to destroy Earth just by ramming into it, never mind cause high-end natural disasters. For reference, the largest recorded earthquake has a magnitude of 9.5 and let out an energy of 2.68 gigatons of TNT. Hurricanes cause wider-scale destruction than earthquakes and they let out 130 petajoules (31.07 megatons of TNT) per day.
A barracuda only needs to be 1600 meters (1.6 kilometers) long just for its proportional KE to match a Magnitude 9.5 earthquake: https://prnt.sc/DF4ldbTm3RMS
Under our current earthquake calc formulae, assuming a Richter magnitude of 5 and a distance of 20037.5 km (half the circumference) is enough to be considered a global earthquake, the earthquake would be sitting at a magnitude of 12.23: https://prnt.sc/KXQI66Y74G51
That's equal to 33.7 teratons of TNT: https://prnt.sc/hS4yfplOgSTl
Let's use this formula for large size KE: (x³m)(x*v)²/2; x is how many times larger than normal a creature is, m is the mass, and v is the velocity.
m=9; v=15.6464
(x³9)(x*15.6464)²/2=1.410008*10^23
9x³*(15.6464x)²/2=1.410008*10^23
1101.644248x^5=1.410008*10^23
x^5=1.279912279*10^20
x=10505.96721
(x³9)(x*15.6464)²/2=1.410008*10^23
9x³*(15.6464x)²/2=1.410008*10^23
1101.644248x^5=1.410008*10^23
x^5=1.279912279*10^20
x=10505.96721
Basing things off this, you'd need a barracuda that's 10505.96721 meters. That itself would make the barracuda visible from the ISS.
If it were a human, it'd be more like this:
m=62; v=5.55
(x³62)(x*5.55)²/2=1.410008*10^23
62x³*(5.55x)²/2=1.410008*10^23
954.8775x^5=1.410008*10^23
x^5=1.476637579*10^20
x=10810.72409
(x³62)(x*5.55)²/2=1.410008*10^23
62x³*(5.55x)²/2=1.410008*10^23
954.8775x^5=1.410008*10^23
x^5=1.476637579*10^20
x=10810.72409
Multiply that by the average height of 5'9" (1.7526 meters) and you get the height requirement of 18946.87503 meters for a human's KE to cause a global earthquake.
As such, ideally, we should better define or break up Type 4 Large Size. The minimum requirements for visibility from space (assuming 1 arcminute as the smallest visible angle) is as such (figures done when angle is set to "Minutes" and 8 sig figs are set): https://www.1728.org/angsize.htm
Karman Line (100 km; current definition of space): 29.088821 meters
ISS (408.773376 km): 118.90736 meters
GPS Satellite (20200 km): 5875.9419 meters
As for the figures required to cause a global earthquake (Magnitude 5 at the furthest point touchable on Earth), here's what I got.:
Great Barracuda (thin organism): 10505.96721 meters (block area of 16.171 km²)
Human (often used as a base for VBW): 18946.87503 meters (cross-sectional area of 244.11 km² based on human cross-sectional area of 0.68 m²)
As for the area nonsense... Yeah, get rid of it. If you can see and make out Florida's shape from a GPS satellite, then maybe the millions of square kilometers thing should be considered a stupid idea.
By the way, I was able to distinguish 1-millimeter-tall letters on a small ruler from half a meter, which is 6.87 arcminutes. Using that figure means I can distinguish the shape of something that's 40.4 km in size if I'm on a GPS satellite.
If a new size tier is required after the Type 4 Large Size fix, I considered something like this:
"Type 5 (Lunar): At this size, the character would be large enough to be visible if he or she were as far from us as the moon is. Characters starting at X km fit this memo"
This would be as such:
Minimum Visible (1 arcminute): 111.8 km
Minimum Distinguishable (based on my ruler eyeballing): 768.8 km
So yeah, there you have it.
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