Tensei Shitara Slime Datta Ken Discussion Thread 20

[MrTim]

Thanks, please do help

The formula for calculating the gravitational force:

F = G * (M * m) / r^2


Sun:

• F is the force of gravity (Newtons)
• G is the gravitational constant (6.674 * 10^-11 Nm^2/kg^2)
• m1 is the mass of object 1 (kg) (mass of the Sun: 1.989 * 10^30 kg)
• m2 - object weight 2 (kg) (object weight: 70 kg) (human)
• r is the distance between the centers of mass of objects (meters) (1 meter)

Calculation:

F = 6.674 * 10^-11 * (1.989 * 10^30 * 70) / 1^2

F ≈ 9.28 * 10^21 N

Therefore, the gravitational force of the Sun on an object weighing 70 kg at a distance of 1 meter from it will be approximately 9.28 * 10^21 Newtons.


Massive Star like Betelgeuse :

• Betelgeuse mass (M): Approximately 11.6 solar masses, which is about 2.31 x 10^31 kg.
• Gravitational constant (G): 6.674 x 10^-11 N(m/kg)^2
• Object weight (m): 70 kg (human)
• Distance from the center of Betelgeuse to the object (r): 1 meter

Calculation:

F = 6.674 x 10^-11 * (2.31 x 10^31 * 70) / 1^2

F ≈ 1.08 x 10^24 N

The gravitational force of Betelgeuse on an object weighing 70 kg at a distance of 1 meter from the star will be approximately 1.08 x 10^24 Newtons.

 

[Mizuki67]

The formula for calculating the gravitational force:

F = G * (M * m) / r^2


Sun:

• F is the force of gravity (Newtons)
• G is the gravitational constant (6.674 * 10^-11 Nm^2/kg^2)
• m1 is the mass of object 1 (kg) (mass of the Sun: 1.989 * 10^30 kg)
• m2 - object weight 2 (kg) (object weight: 70 kg) (human)
• r is the distance between the centers of mass of objects (meters) (1 meter)

Calculation:

F = 6.674 * 10^-11 * (1.989 * 10^30 * 70) / 1^2

F ≈ 9.28 * 10^21 N

Therefore, the gravitational force of the Sun on an object weighing 70 kg at a distance of 1 meter from it will be approximately 9.28 * 10^21 Newtons.


Massive Star like Betelgeuse :

• Betelgeuse mass (M): Approximately 11.6 solar masses, which is about 2.31 x 10^31 kg.
• Gravitational constant (G): 6.674 x 10^-11 N(m/kg)^2
• Object weight (m): 70 kg (human)
• Distance from the center of Betelgeuse to the object (r): 1 meter

Calculation:

F = 6.674 x 10^-11 * (2.31 x 10^31 * 70) / 1^2

F ≈ 1.08 x 10^24 N

The gravitational force of Betelgeuse on an object weighing 70 kg at a distance of 1 meter from the star will be approximately 1.08 x 10^24 Newtons.

So pre stellar?

 

[Mizuki67]

sorry, Class Z

 

[Mizuki67]

that means AP is around planet level or moon level

 

[MrTim]

that is

 

[Digital_Franz]

What did Jozay do to get banned?

 

[Mizuki67]

What did Jozay do to get banned?

Put nonduality on izis profile without approval

 

[Digital_Franz]

Put nonduality on izis profile without approval

Damn. And for how long is he banned?

 

[Mizuki67]

Damn. And for how long is he banned?

2 years, well permanently actually (he says he isn't coming back)

 

[Digital_Franz]

that means AP is around planet level or moon level

This would tie in well with characters like Carrera, Ultima, and Testarossa during the invasion of the empire before being able to use their power to hurt Velgrynd

 

[Digital_Franz]

2 years, well permanently actually (he says he isn't coming back)

OK

 

[CodeCCLL]

one calc supporter joxay is banned

Can you stop mention nonsense about Jozay, he doesn't have any accepted calculations and I haven't seen he try it, it really disrespects the efforts of those who make the calculations.

 

[Mizuki67]

Can you stop mention nonsense about Jozay, he doesn't have any accepted calculations and I haven't seen he try it, it really disrespects the efforts of those who make the calculations.

I said that "i have seen"
He did a very good calc on rimuru absorption speed but it was denied base on there wasn't any time frame
I haven't seen any other calc from this verse except from @Catpija so far have i, also how is this even offensive?

This would tie in well with characters like Carrera, Ultima, and Testarossa during the invasion of the empire before being able to use their power to hurt Velgrynd

Carrera gravity collapse need calculations too lol
Porbably be around star level, perhaps?
Idk, but her own is an accurate black hole so...

 

[Digital_Franz]

Carrera gravity collapse need calculations too lol
Porbably be around star level, perhaps?
Idk, but her own is an accurate black hole so...

In general they will all need to be recalculated considering the x100 more solid in the Cardinal world. Carrera's Gravity Collapse would indeed be star level. The character like Hinata would surely be planet level or large planet

 

[Mizuki67]

In general they will all need to be recalculated considering the x100 more solid in the Cardinal world. Carrera's Gravity Collapse would indeed be star level. The character like Hinata would surely be planet level or large planet

Moon level actually
Anyways, carrera is already 2-C, the star level bit isnt necessary
We did the calcs @MrTim helped out
And they seem to be small planet/large moon level (we can just say planet level ngl)
With LS of class Z
True dragons LS should then be stellar or multi-stellar with this scan

Gyazo

gyazo.com

 

[Mizuki67]

that is

I was wondering if you could all your calcs in a blog btw
This is the scan

The scan that it is legitimate since it is better than kumara gravity manip

 

[Digital_Franz]

Moon level actually
Anyways, carrera is already 2-C, the star level bit isnt necessary

Maybe for Kondou scaling later

We did the calcs @MrTim helped out
And they seem to be small planet/large moon level (we can just say planet level ngl)
With LS of class Z

It's true. I jumped through the levels very quickly without using good logic

 

[Meli_Tempest]

The formula for calculating the gravitational force:

F = G * (M * m) / r^2


Sun:

• F is the force of gravity (Newtons)
• G is the gravitational constant (6.674 * 10^-11 Nm^2/kg^2)
• m1 is the mass of object 1 (kg) (mass of the Sun: 1.989 * 10^30 kg)
• m2 - object weight 2 (kg) (object weight: 70 kg) (human)
• r is the distance between the centers of mass of objects (meters) (1 meter)

Calculation:

F = 6.674 * 10^-11 * (1.989 * 10^30 * 70) / 1^2

F ≈ 9.28 * 10^21 N

Therefore, the gravitational force of the Sun on an object weighing 70 kg at a distance of 1 meter from it will be approximately 9.28 * 10^21 Newtons.


Massive Star like Betelgeuse :

• Betelgeuse mass (M): Approximately 11.6 solar masses, which is about 2.31 x 10^31 kg.
• Gravitational constant (G): 6.674 x 10^-11 N(m/kg)^2
• Object weight (m): 70 kg (human)
• Distance from the center of Betelgeuse to the object (r): 1 meter

Calculation:

F = 6.674 x 10^-11 * (2.31 x 10^31 * 70) / 1^2

F ≈ 1.08 x 10^24 N

The gravitational force of Betelgeuse on an object weighing 70 kg at a distance of 1 meter from the star will be approximately 1.08 x 10^24 Newtons.

This is good, less complicated than my idea

But why Betelgeuse? The minimum mass for a star to be considered massive is plus or minus 8 solar masses, Betelgeuse has around 20, it would be better to consider a low and a high ball for the calculation, Be can serve as a medium ball I guess.

I propose this:

Low ball: 8 solar masses

Medium ball: 20

High ball 30, which is about the amount of mass needed to start forming black holes.

Although this may change at the discretion of some staff.

 

[Mizuki67]

This is good, less complicated than my idea

But why Betelgeuse? The minimum mass for a star to be considered massive is plus or minus 8 solar masses, Betelgeuse has around 20, it would be better to consider a low and a high ball for the calculation, Be can serve as a medium ball I guess.

I propose this:

Low ball: 8 solar masses

Medium ball: 20

High ball 30, which is about the amount of mass needed to start forming black holes.

Although this may change at the discretion of some staff.

Can you put all of this into a blog?
Lets get the calc observed

 

[Meli_Tempest]

As for Carrera's feat, to calculate black holes we need data that the novel does not provide, so we may have to wait until the appearance of the feat in the anime or manga.

 

[Meli_Tempest]

If you give me a few hours, of course, I'd be happy to, I'll be busy.

 

[Mizuki67]

As for Carrera's feat, to calculate black holes we need data that the novel does not provide, so we may have to wait until the appearance of the feat in the anime or manga.

Forget about that one
I'll handle it
You can add the minitz issue first
Then we can get LS feat evaluated

 

[Mizuki67]

If you give me a few hours, of course, I'd be happy to, I'll be busy.

Thank you

 

[MrTim]

I was wondering if you could all your calcs in a blog btw
This is the scan

The scan that it is legitimate since it is better than kumara gravity manip

Im not good at editing content or creating blogs, so... sorry

 

[Mizuki67]

Im not good at editing content or creating blogs, so... sorry

Its all good thanks
Can you atleast do a low ball, mid ball and high ball scaling of this feat

 

[MrTim]

Its all good thanks
Can you atleast do a low ball, mid ball and high ball scaling of this feat

ok np

 

[MrTim]

It seems I made a mistake in calculating Betelgeuse ehe~
btw rating will remain the same, within Class Z

The formula for calculating the gravitational force:

F = G * (M * m) / r^2

Low Ball: Spica is about 10 times more massive than the Sun.

The weight of the Spica = 10 * 1.989 * 10 ^30 kg = 1.989 * 10^31 kg

• F is the force of gravity (in Newtons)
• G is the gravitational constant (6.674 * 10^-11 N * m^2/kg^2)
• m1 is the mass of the Spica (1.989 * 10^31 kg)
• m2 - object weight (70 kg) (human)
• r is the distance between the centers of mass (1 meter)

F = 6.674 * 10^-11 * (1.989 * 10^31 * 70) / 1^2

F ≈ 9.29 * 10^22 N

Thus, the gravitational force acting on an object weighing 70 kg at a distance of 1 meter from the center of the Spica would be approximately 9.29 * 10^22 Newtons.

Mid ball: Deneb is about 20 times more massive than the Sun.

The mass of the Deneb = 20 * 1.989 * 10 ^30 kg = 3.978 * 10^31 kg

• F is the force of gravity (in Newtons)
• G is the gravitational constant (6.674 * 10^-11 N * m^2/kg^2)
• m1 is the mass of Deneb (3.978 * 10^31 kg)
• m2 - object weight (70 kg) (human)
• r is the distance between the centers of mass (1 meter)

F = 6.674 * 10^-11 * (3.978 * 10^31 * 70) / 1^2

F ≈ 1.858 * 10^23 N

Thus, the gravitational force acting on an object weighing 70 kg at a distance of 1 meter from the center of Deneb would be approximately 1.858 * 10^23 Newtons

High ball: Random unknown star is about 30 times more massive than the Sun.

The mass of Random unknown star = 30 * 1.989 * 10^30 kg = 5.967 * 10^31 kg

• F is the force of gravity (in Newtons)
• G is the gravitational constant (6.674 * 10^-11 N * m^2/kg^2)
• m1 is the mass of the star (5.967 * 10^31 kg)
• m2 - object weight (70 kg) (human)
• r is the distance between the centers of mass (1 meter)

F = 6.674 * 10^-11 * (5.967 * 10^31 * 70) / 1^2

F ≈ 2.787 * 10^23 N

Thus, the gravitational force acting on an object weighing 70 kg at a distance of 1 meter from the center of a star would be approximately 2.787 * 10^23 Newtons.

 

[Mizuki67]

It seems I made a mistake in calculating Betelgeuse ehe~
btw rating will remain the same, within Class Z

The formula for calculating the gravitational force:

F = G * (M * m) / r^2

How about kumara who's gravity can interfere with planets?
That should make the lifting strength planet level at the least right?

 

[MrTim]

How about kumara who's gravity can interfere with planets?
That should make the lifting strength planet level at the least right?

As far as I understand it should be at least Class E, since it can manipulate planets despite the gravitational force of local star
(I take into account a star comparable to sun)

pushing a planet or a star is not the same as destroying it, space-time itself is taken into account here as the fabric on which these stars are located.
Well, that's how physics works.

 

[Meli_Tempest]

How about kumara who's gravity can interfere with planets?
That should make the lifting strength planet level at the least right?

Planet Level Slime?

vsbattles.fandom.com

I made the blog, although it doesn't really look anything impressive, I think I didn't get anything wrong, but you can take a look at it, I must sleep.

Pd: remembering I decided to change the mid and highball thanks to a friend's reminder that the maximum possible mass is 150 solar masses.
.

 

[Mizuki67]

As far as I understand it should be at least Class E, since it can manipulate planets despite the gravitational force of local star
(I take into account a star comparable to sun)

pushing a planet or a star is not the same as destroying it, space-time itself is taken into account here as the fabric on which these stars are located.
Well, that's how physics works.

Alright, thanks a bjcb

Planet Level Slime?

vsbattles.fandom.com

I made the blog, although it doesn't really look anything impressive, I think I didn't get anything wrong, but you can take a look at it, I must sleep.

Pd: remembering I decided to change the mid and highball thanks to a friend's reminder that the maximum possible mass is 150 solar masses.
.

This will help

 

[Mizuki67]

let me contact @KLOL506

 

[Mizuki67]

Well screw it ig

Stellar level lifting strength (Revision of Tensura)

well, we haven't gotten any answer from any calc mod on the AP ratings, but LS seems straightforward, okay here we go The Force exerted The force exerted is the GF (gravitational force, tensile force, Crushing force), was on par with a massive star That was Oppressor, his unique skill, and it...

vsbattles.com

 

[Eikichi_Sensei]

My first Slime CRT (Tensura): Adding things and questions.

Good morning/afternoon/night. This is my first CRT of adding things to Rimuru's profile. I would like Slime Rimuru to have Low Godly for the following reasons: https://imgur.com/gallery/x8lgODc https://imgur.com/gallery/8qV9gpK I was also wondering if anyone would be kind enough to answer...

vsbattles.com

 

[Meli_Tempest]

Planet Level Slime?

vsbattles.fandom.com

I fixed all the little details and I think it works smoothly now.

 

[Mizuki67]

My first Slime CRT (Tensura): Adding things and questions.

Good morning/afternoon/night. This is my first CRT of adding things to Rimuru's profile. I would like Slime Rimuru to have Low Godly for the following reasons: https://imgur.com/gallery/x8lgODc https://imgur.com/gallery/8qV9gpK I was also wondering if anyone would be kind enough to answer...

vsbattles.com

Ohh christ
Of course everyone wants to open a CRT

Planet Level Slime?

vsbattles.fandom.com

I fixed all the little details and I think it works smoothly now.

Let me take a look

 

[Mizuki67]

Planet Level Slime?

vsbattles.fandom.com

I fixed all the little details and I think it works smoothly now.

This is very nicely done
I am starting to dislike how this wiki handles matters, why doesnt no one wants to atleast go through the calcs?
I'll find a way anyway

 

[Mizuki67]

Hey everyone, @CodeCCLL sorry to say but we have decided to yank our CM1 for SPL and magic back to type 2
It feels and sounds stupid, there's also numerous wanks on it, if someone was serious, downgrading that thing would take less than no time at all

 

[Eikichi_Sensei]

So only True Dragon will keep CM 1?

 

[Mizuki67]

So only True Dragon will keep CM 1?

Safe to say, yes
Reasons:

1. It is consistent with the storyline
2. It have backups and better wordings to it

That's why i have decided to remove CM1 from magic, also ultimate skills can probably keep theirs as well
I have my reasons for that too