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Hydrogen H2 is a two atomic gas to its internal energy is:
E = 3/2nRT
In adiobatic process temperature ratio is T2/T1 = (V1/V2)^(R/C)
so T2 = T1*(V1/V2)^(R/C)
E = 3/2nR*T1*(V1/V2)^(R/C)
From the calc above: V2 = 8πMG/c^2 and V1 = M/ρH2
E = 3/2nR*T1*((M/ρ)/(8πMG/c^2))^(R/C)
E =...
Like I said before a valid LS feat in my opinion should be performed continuously. I don't think I have much more to add to this. This is only a mater of how many people agree with me.
As it has been pointed out already striking a baseball would output an absolutely huge amount of force. This...
About lifting strength. I suggest we add a new rule. Something along the lines "A valid lifting strength feat should be performed for a duration of at least several seconds"
Just because a character can launch a football to space or punch a dent in a sheet of metal doesn't mean he can exort...
Positive and negative torques acting on the rod are equal in magnitude as long as the rod is static. So it doesn't mater if we chose those that act in clockwise or counter-clockwise direction.
In that case we can define bending moment M as counter-clockwise torque at that point.
M = N1*x+N2*(y+z).
Force F is not in the equation since it acts in the opposite direction.
In statics sum of all forces acting on the rod has to be zero, otherwise it would accelerate in the direction of...
...force is aplied.
As you can see in the picture above, the only force that wants to rotate the rod clockwise is F2. Wherefore bending moment is F2*y
I do agree that the result seems counter intuitive. After all it means that the force is independent on the length or the rod as well as the...
Okay so in this case we have two forces aplied in the opposite directions y distance appart from each other like in the picture below:
Since both F1 and F2 are aplied by a single hand they have to be equal due to Newton's third law.
In order to find the bending moment M we have to figure...
This is not about complexity either. I don't find my method any more compicated since it only uses different values and take into account the level of fragmentanion. But doing that would require us to revise tens of thousands of profiles and pages and nobody wants to do that.
Yes, unfortunately this formula only works for bending long poles or flat sheets across their entire length. I have absolutely no idea or how to calcute a randomly shaped dent on a flat sheet
In this context moment of inertia means this. It is used to calculate elastic section modulus. The mass moment of inertia is calculated in a very similar way hence the same name. In fact if we multiply area moment of inertia by density we will get mass moment of inertia where neutral axis turns...
This V bending calculator uses the method I've shown above. It assumes rectangular cross section, fully plactic deformation, and 3-point bending (case 3 in the picture above). It also uses ultimate tensile strength instead of yeild strength to get the highest result posible. Yeild strength is...
Since the whole thing was never resolved I'm going to explain bending formula.
I am not going to cover the math explaining how it works (Although I can do it in case further explanation is required) but I am going to make a quick guide.
If the bending deformation is plastic the first thing we...
Is this thread still relevant?
https://vsbattles.com/threads/indentation-calcs.159931/
I'm probably the first user to use this method for bending metal and I believe I have a really good understaning on how it actually works
In this secific case KE is calculated differently. KE = 0.4πρ(R^5-r^5)/t^2 where ρ is density of the planet. R and r are radii of the planet before and after the contraction. I derived this formula with DontTalkTD a while ago.
How does Stark only have average human lifting strength? I definatly remember Eisen lifting a big boulder over his head. Like Class 100 big. Even if the doesn't somehow scale it should be at least athletic level.
Also why do mages have 10-B psysicaly tier? Is that even important?
No.
This formula assumes 70 degree FoV hence there is tan(35) in it. When you're using a portion of the original image we know for a fact that your FoV is below 70 degrees and we can no longer use that assumption.
There is definatly something wrongwith these fire calcs. This fire tornado is nothing compared to 12 kT nuke that was droped on Hiroshima in terms of both size of the fire blast and its temperature.
I don't understand what the problem is. Type A uncertainty always exists even if we don't take multiple measurements to assess it. It all makes sense from metrological standpoint if we can consider the author an uncertainty contributor
I agree with the AP there. All measurements are acurate to a degree and every measured value has an uncertainty. Taking multiple measurements to calculate the average actually does reduce type A uncertenty/stardart error hence making our final result more accurate.
There's one huge problem with black flash. It is stated that black flash amplifies the attack to the 2.5 power which doesn't make any scence if you think about it. It cannot even be evaluated numerically
Last hypersonic calc is invalid since the truck rotates across the axis passing though its centel and centrifugal force only describes the stress the truck experiences. In fact even if centrifugal force does push agains the umbrella you only need to push it upwards to counter that force. There's...